There was a post this morning asking about how many people disable JavaScript. Then I began to wonder what techniques might be used to determine if the user has it disabled.
I would like to add my solution to get reliable statistics on how many real users visit my site with javascript disabled over the total users. The check is done one time only per session with these benefits:
My code uses PHP, mysql and jquery with ajax but could be adapted to other languanges:
Create a table in your DB like this one:
CREATE TABLE IF NOT EXISTS `log_JS` (
`logJS_id` int(11) NOT NULL AUTO_INCREMENT,
`data_ins` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`session_id` varchar(50) NOT NULL,
`JS_ON` tinyint(1) NOT NULL DEFAULT '0',
`agent` varchar(255) DEFAULT NULL,
PRIMARY KEY (`logJS_id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
Add this to every page after using session_start() or equivalent (jquery required):
if (!isset($_SESSION["JSTest"]))
{
mysql_query("INSERT INTO log_JS (session_id, agent) VALUES ('" . mysql_real_escape_string(session_id()) . "', '" . mysql_real_escape_string($_SERVER['HTTP_USER_AGENT']). "')");
$_SESSION["JSTest"] = 1; // One time per session
?>
}
?>
Create the page JSOK.php like this:
include_once("[DB connection file].php");
mysql_query("UPDATE log_JS SET JS_ON = 1 WHERE session_id = '" . mysql_real_escape_string(session_id()) . "'");