cout << with char* argument prints string, not pointer value

Question

This:

const char * terry = \"hello\";
cout<

prints hello instead of the memory address of the \'h\'.

Answer 1

"hello" is a string, i.e. the char array. const char* is a pointer to this array, so when you dereference this pointer, you get the value of the first element.

It is like if you have

int a[] = {1, 2, 3};
int *b = a;
cout << *b << endl;

you get just 1 printed.