Passing capturing lambda as function pointer

Question

Is it possible to pass a lambda function as a function pointer? If so, I must be doing something incorrectly because I am getting a compile error.

Consider the follo

Answer 1

Not a direct answer, but a slight variation to use the "functor" template pattern to hide away the specifics of the lambda type and keeps the code nice and simple.

I was not sure how you wanted to use the decide class so I had to extend the class with a function that uses it. See full example here: https://godbolt.org/z/jtByqE

The basic form of your class might look like this:

template 
class Decide
{
public:
    Decide(Functor dec) : _dec{dec} {}
private:
    Functor _dec;
};

Where you pass the type of the function in as part of the class type used like:

auto decide_fc = [](int x){ return x > 3; };
Decide greaterThanThree{decide_fc};

Again, I was not sure why you are capturing x it made more sense (to me) to have a parameter that you pass in to the lambda) so you can use like:

int result = _dec(5); // or whatever value

See the link for a complete example