The easiest way, would be to do a trick like this;
double val = ....;
val = val*100;
val = Math.round(val);
val = val /100;
if val starts at 200.3456 then it goes to 20034.56 then it gets rounded to 20035 then we divide it to get 200.34.
if you wanted to always round down we could always truncate by casting to an int:
double val = ....;
val = val*100;
val = (double)((int) val);
val = val /100;
This technique will work for most cases because for very large doubles (positive or negative) it may overflow. but if you know that your values will be in an appropriate range then this should work for you.