Say that I have this data frame:
1 2 3 4
100 8 12 5 14
99 1 6 4 3
98 2 5 4 11
97 5 3 7 2
<
Here's a solution using stack()
, and aggregate()
, although it requires the second data.frame contain character vectors, as opposed to factors (could be forced with lapply(df2,as.character)
):
df1 <- data.frame(a=c(8,1,2,5), b=c(12,6,5,3), c=c(5,4,4,7), d=c(14,3,11,2) );
df2 <- data.frame(a=c('A','B','C','D'), b=c('B','C','D','E'), c=c('C','D','E','F'), d=c('D','E','F','G'), stringsAsFactors=F );
aggregate(sum~group,data.frame(sum=stack(df1)[,1],group=stack(df2)[,1]),sum);
## group sum
## 1 A 8
## 2 B 13
## 3 C 13
## 4 D 28
## 5 E 10
## 6 F 18
## 7 G 2