Say that I have this data frame:
1 2 3 4
100 8 12 5 14
99 1 6 4 3
98 2 5 4 11
97 5 3 7 2
<
You can use row()
and col()
to identify row/column relationships.
m <- read.table(text="
1 2 3 4
100 8 12 5 14
99 1 6 4 3
98 2 5 4 11
97 5 3 7 2")
vals <- sapply(2:8,
function(j) sum(m[row(m)+col(m)==j]))
or (as suggested in comments by ?@thelatemail)
vals <- sapply(split(as.matrix(m), row(m) + col(m)), sum)
data.frame(group=LETTERS[seq_along(vals)],sum=vals)
or (@Frank)
data.frame(vals = tapply(as.matrix(m),
(LETTERS[row(m) + col(m)-1]), sum))
as.matrix()
is required to make split()
work correctly ...