Error on async job

前端 未结 4 1365
轻奢々
轻奢々 2021-02-20 16:39

I\'m trying to create an async task that will not block the request. The user make the request, the task will start, and the controller will render \"Job is running...\", this i

4条回答
  •  情书的邮戳
    2021-02-20 17:04

    I was able to get rid of this exception in a controller by removing the onComplete and onError calls. I guess the exception happens because the parent thread ended when you called render.

    So your:

    Promise p = task {
        complexAsyncMethodCall(); // (1) do stuff
    }
    .onComplete { result -> println result } // (2) on success
    .onError { Throwable t -> System.err.println("Error: " + t) } // (3) on error
    

    Becomes:

    Promise p = task {
        try {
            def result = complexAsyncMethodCall(); // (1) do stuff
            println result // (2) on success
        } catch(Throwable t) {
            System.err.println("Error: " + t) // (3) on error
        }
    }
    

    This adds coupling between your work (1) and the result processing (2 and 3) but you could overcome this by writing your own Closure wrapper that takes extra Closures as arguments. Something like this:

    // may not work! written off the top of my head
    class ProcessableClosure extends Closure {
        Closure work;
        Closure onError;
        Closure onComplete;
    
        @Override
        public V call(Object... args) {
            try {
                def result = work.call(args); // (1) do stuff
                onComplete.call(result); // (2) on complete
            } catch(Exception e) {
                onError.call(result); // (3) on error
            }
        }
    }
    

    That makes your code more readable:

    Closure doWork = { complexAsyncMethodCall(); } // (1) do stuff
    Closure printResult = { println it } // (2) on complete
    Closure logError = { Throwable t -> log.error t } // (3) on error
    Closure runEverythingNicely = new ProcessableClosure(work: doWork, onComplete: printResult, onError: logError)
    Promise p = task { runEverythingNicely }
    

提交回复
热议问题