Regex is behaving lazy, should be greedy

Question

I thought that by default my Regex would exhibit the greedy behavior that I want, but it is not in the following code:

 Regex keywords = new Reg         


        

Answer 1

It looks like you're trying to word break things. To do that you need the entire expression to be correct, your current one is not. Try this one instead..

new Regex(@"\b(in|int|into|internal|interface)\b");

The "\b" says to match word boundaries, and is a zero-width match. This is locale dependent behavior, but in general this means whitespace and punctuation. Being a zero width match it will not contain the character that caused the regex engine to detect the word boundary.