How to remove seconds from datetime?

Question

I have the following date and I tried the following code,

df[\'start_date_time\'] = [\"2016-05-19 08:25:00\",\"2016-05-19 16:00:00\",\"2016-05-20 07:45:00\",\"20         


        

Answer 1

Convert the string to a datetime object and then manipulate that

>>> x = ["2016-05-19 08:25:00","2016-05-19 16:00:00","2016-05-20 07:45:00","2016-05-24 12:50:00","2016-05-25 23:00:00","2016-05-26 19:45:00"]
>>> for i in x:
...  y = datetime.datetime.strptime(i, '%Y-%m-%d %H:%M:%S')
...  z = datetime.datetime.strftime(y, '%Y-%m-%d %H:%M')
...  print (y, type(y))
...  print (z, type(z))
... 
(datetime.datetime(2016, 5, 19, 8, 25), )
('2016-05-19 08:25', )
(datetime.datetime(2016, 5, 19, 16, 0), )
('2016-05-19 16:00', )
(datetime.datetime(2016, 5, 20, 7, 45), )
('2016-05-20 07:45', )
(datetime.datetime(2016, 5, 24, 12, 50), )
('2016-05-24 12:50', )
(datetime.datetime(2016, 5, 25, 23, 0), )
('2016-05-25 23:00', )
(datetime.datetime(2016, 5, 26, 19, 45), )
('2016-05-26 19:45', )