I have the following date and I tried the following code,
df[\'start_date_time\'] = [\"2016-05-19 08:25:00\",\"2016-05-19 16:00:00\",\"2016-05-20 07:45:00\",\"20
You can subtract the seconds using a timedelta:
import datetime d = datetime.datetime.now() #datetime including seconds without_seconds = d - datetime.timedelta(seconds=d.second)