Why is my overloaded C++ constructor not called?

Question

I have a class like this one:

class Test{
public:
  Test(string value);
  Test(bool value);

};

If I create an object like this:

Answer 1

The type of "Just a test..." is const char *, which can be implicitly converted to either bool or std::string. Because std::string isn't a built in type, the const char *s is converted to a bool. You can prevent that by explicitly converting the const char * to a std::string:

Test test(std::string("Just a test..."));