In function call, why doesn't nullptr match a pointer to a template object?

Question

Here is an example of a code that works perfectly:

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#include
#include

template< class D, template< class D, class A >         


        

Answer 1

That's to prevent you from creating a template that has nullptr as a argument. You most likely don't want that. You want the template to use a propper class as an argument and take nullptr as a value for that argument.

You can either

• explicitly call the right version of the template
• cast nullptr to a propper type for the template.
• create a local var of the right pointer type, give it value nullptr and make the call using that var.