What is happening during `delete this;` statement?

Question

Please consider the following code:

class foo
{
public:
    foo(){}
    ~foo(){}
    void done() { delete this;}
private:
    int x;
};

What is

Answer 1

In both cases your heap will get corrupted. Of course, you can't use in option 2 "->" if the left value (in this case, "a") is not a pointer, the correct form in option 2 would be a.done(); But yeah, you should get a heap corruption if you try to delete 1) what's been already deleted, or 2) local variable.

Calling "delete this" is technically valid and frees the memory.

EDIT I was curious and actually tried this:

class foo 
{
public: 
    foo(){} 
    ~foo(){} 
    void done() { delete this; } 
    void test() { x = 2; }
    int getx() { return x; }
private: 
    int x; 
} ;


int main(int argc, char* argv[])
{
    foo *a = new foo();
    a->done();
    a->test();
    int x = a->getx();
    printf("%i\n", x);
    return x;
}

A call to printf will succeed, and x will hold the value 2.