Extract filename and extension in Bash

Question

I want to get the filename (without extension) and the extension separately.

The best solution I found so far is:

NAME=`echo \"$FILE\" | cut -d\'.\'          


        

Answer 1

How to extract the filename and extension in fish:

function split-filename-extension --description "Prints the filename and extension"
  for file in $argv
    if test -f $file
      set --local extension (echo $file | awk -F. '{print $NF}')
      set --local filename (basename $file .$extension)
      echo "$filename $extension"
    else
      echo "$file is not a valid file"
    end
  end
end

Caveats: Splits on the last dot, which works well for filenames with dots in them, but not well for extensions with dots in them. See example below.

Usage:

$ split-filename-extension foo-0.4.2.zip bar.tar.gz
foo-0.4.2 zip  # Looks good!
bar.tar gz  # Careful, you probably want .tar.gz as the extension.

There's probably better ways to do this. Feel free to edit my answer to improve it.

---

If there's a limited set of extensions you'll be dealing with and you know all of them, try this:

switch $file
  case *.tar
    echo (basename $file .tar) tar
  case *.tar.bz2
    echo (basename $file .tar.bz2) tar.bz2
  case *.tar.gz
    echo (basename $file .tar.gz) tar.gz
  # and so on
end

This does not have the caveat as the first example, but you do have to handle every case so it could be more tedious depending on how many extensions you can expect.