Extract filename and extension in Bash

Question

I want to get the filename (without extension) and the extension separately.

The best solution I found so far is:

NAME=`echo \"$FILE\" | cut -d\'.\'          


        

Answer 1

You can use the magic of POSIX parameter expansion:

bash-3.2$ FILENAME=somefile.tar.gz
bash-3.2$ echo "${FILENAME%%.*}"
somefile
bash-3.2$ echo "${FILENAME%.*}"
somefile.tar

---

There's a caveat in that if your filename was of the form ./somefile.tar.gz then echo ${FILENAME%%.*} would greedily remove the longest match to the . and you'd have the empty string.

(You can work around that with a temporary variable:

FULL_FILENAME=$FILENAME
FILENAME=${FULL_FILENAME##*/}
echo ${FILENAME%%.*}

)

---

This site explains more.

${variable%pattern}
  Trim the shortest match from the end
${variable##pattern}
  Trim the longest match from the beginning
${variable%%pattern}
  Trim the longest match from the end
${variable#pattern}
  Trim the shortest match from the beginning