C++0x issue: Constant time insertion into std::set

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生来不讨喜
生来不讨喜 2021-02-20 04:21

According to this page, I can achieve constant time insertion if I use

iterator std::set::insert ( iterator position, const value_type& x );
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4条回答
  •  谎友^
    谎友^ (楼主)
    2021-02-20 04:46

    Is it cheating to run a test instead of reading through library specifications?

    For g++-4.4 -O2 for the integers 0 <= i < 5000000 my running times for standard insertion are

    real    0m14.952s
    user    0m14.665s
    sys 0m0.268s
    

    and my running times for insertion using end() as hint are

    real    0m4.373s
    user    0m4.148s
    sys 0m0.224s
    

    Insertion at end() - 1 is just as fast as far as I can tell, but it is more cumbersome to use because end() - 1 is an illegal operation (you have to use operator--()) and it crashes if the set happens to be empty.

    #include 
    
    typedef std::set Set;
    
    void insert_standard(Set& xs, int x)
    {
        xs.insert(x);
    }
    
    void insert_hint_end(Set& xs, int x)
    {
        xs.insert(xs.end(), x);
    }
    
    int main()
    {
        const int cnt = 5000000;
        Set xs;
        for (int i = 0; i < cnt; i++) {
            // insert_hint_end(xs, i);
            insert_standard(xs, i);
        }
    }
    

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