bash: getting percentage from a frequency table

Question

i had made a small bash script in order to get the frequency of items in a certain column of a file.

The output would be sth like this

A     30
B     25
         


        

Answer 1

Change your awk command to something like this:

awk '{ a[++n,1] = $2; a[n,2] = $1; t += $1 }
     END {
         for (i = 1; i <= n; i++)
             printf "%-20s %-15d%d%%\n", a[i,1], a[i,2], 100 * a[i,2] / t
     }'