bash: getting percentage from a frequency table

Question

i had made a small bash script in order to get the frequency of items in a certain column of a file.

The output would be sth like this

A     30
B     25
         


        

Answer 1

Try this (with the sort moved to the end:

cut -f $1 $2| sort | uniq -c  | awk '{array[$2]=$1; sum+=$1} END { for (i in array) printf "%-20s %-15d %6.2f%%\n", i, array[i], array[i]/sum*100}' | sort -r -k2,2 -n