TypeScript show following error message to this code samples:
class MyClass {
someField: boolean;
constructor() {
return { someField: true };
}
}
strictPropertyInitialization
forces you to initialize all properties that are not optional in the constructor of the class. This check can be useful as it ensures that you don't get unexpected uninitialized properties. There are several ways to get around the error, the first two are the general way to do it, in your case only the last on applies (I include all for completeness):
Initialize the field
If you define the property as boolean
if should be true
or false
initialize it when you declare the field or initialize it in the constructor:
class MyClass {
someField: boolean = false;
constructor() {
return { someField: true };
}
}
Make the field optional
If the field can be undefined
, you should mark this in the field declaration either by using ?
or typing the field as undefined|boolean
class MyClass {
//someField?: boolean;
someField: boolean | undefined;
constructor() {
return { someField: true };
}
}
Use a not null assertion
In your case since in the constructor you are actually not initializing the current object (this
) but returning a new one, you can tell the compiler it is wrong about the error and use a not null assertion. This assertion is specifically introduced because there are limitations in strictPropertyInitialization
checks and sometimes the compiler gets it wrong. For those cases you can override what the compiler thinks, but you have to be explicit about it:
class MyClass {
someField!: boolean;
constructor() {
return { someField: true };
}
}