Can an unnamed parameter of function have a default value?

Question

Is the following code legal in C++?

void f(void* = 0)
{}

int main()
{
    f();
}

Which page of the C++ standard states that this usage is lega

Answer 1

Yes, it's perfectly legal. An obvious example is found in N3485 8.3.6 Default Arguments/4:

[Example: the declaration

void point(int = 3, int = 4);  

declares a function that can be called with zero, one, or two arguments of type int.