Can a C++ lambda constructor argument capture the constructed variable?

Question

The following compiles. But is there ever any sort of dangling reference issue?

    class Foo {
         Foo(std::function fn) { /* etc         


        

Answer 1

But is there ever any sort of dangling reference issue?

That depends entirely on what you're doing with Foo. Here's an example that would have dangling reference issues:

struct Foo {
     Foo() = default;
     Foo(std::function fn) : fn(fn) { }
     std::function fn;
}

Foo outer;
{
    Foo inner([&inner](int i){f(i, inner);});
    outer = inner;
}
outer.fn(42); // still has reference to inner, which has now been destroyed