In array operator in bash

Question

Is there a way to test whether an array contains a specified element?

e.g., something like:

array=(one two three)

if [ \"one\" in ${array} ]; then
...
f         


        

Answer 1

I got an function 'contains' in my .bashrc-file:

contains () 
{ 
    param=$1;
    shift;
    for elem in "$@";
    do
        [[ "$param" = "$elem" ]] && return 0;
    done;
    return 1
}

It works well with an array:

contains on $array && echo hit || echo miss
  miss
contains one $array && echo hit || echo miss
  hit
contains onex $array && echo hit || echo miss
  miss

But doesn't need an array:

contains one four two one zero && echo hit || echo miss
  hit