Regular expression that includes all keyboard characters except '~' and ','

Question

How do I write a regular expression that includes all keyboard characters except \'~\' and \',\'?

Answer 1

A related one.

I wasted a lot of time searching, so below is the answer I came up with.

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I wanted all keyboard keys (including space and tab):

// all keys (including space and tab)
var allKeyboardKeysRegex = /^[a-zA-Z0-9~`!@#\$%\^&\*\(\)_\-\+={\[\}\]\|\\:;"'<,>\.\?\/  ]*$/;

// example tests
var nonShiftChars = "`1234567890-=  qwertyuiop[]\asdfghjkl;'zxcvbnm,./ "
var shiftChars = "~!@#$%^&*()_+{}|:\"<>? ";
var someAlphaNumeric = "aAbB12 89yYzZ";

// test with allKeyboardKeysRegex
allKeyboardKeysRegex.test(nonShiftChars);
allKeyboardKeysRegex.test(shiftChars);
allKeyboardKeysRegex.test(someAlphaNumeric);

Output:

true
true
true

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if you want to exclude some characters, then just delete them from above 1st line regex line (allKeyboardKeysRegex).

Example:

// removing '~' and ','
var allKeyboardKeysRegexMinusSome = /^[a-zA-Z0-9`!@#\$%\^&\*\(\)_\-\+={\[\}\]\|\\:;"'<>\.\?\/   ]*$/;

Hope that will help someone.

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Update

List of all chars

"1234567890"
"abcdefghijklmnopqrstuvwxyz"
"ABCDEFGHIJKLMNOPQRSTUVWXYZ"
"~`!@#$%^&*()_-+={[}]|\:;"'<,>.?/    " (last 2 are space & tab here)
"~`!@#$%^&*()_-+={[}]|\\:;\"'<,>.?/ \t\r\n   " (last 2 are space & tab here, all these chars are escaped with \)