How do you do UUID in Golangs Gorm?

Question

I have the following model...

type User struct {
    ID        string  `sql:\"type:uuid;primary_key;default:uuid_generate_v4()\"`
    FirstName string `form:\"f         


        

Answer 1

For this you will need gorm and go.uuid

go get github.com/jinzhu/gorm

go get github.com/satori/go.uuid

Try creating your own model base model in place of gorm.Model like so:

type Base struct {
 ID         string     `sql:"type:uuid;primary_key;default:uuid_generate_v4()"`
 CreatedAt  time.Time  `json:"created_at"`
 UpdatedAt  time.Time  `json:"update_at"`
 DeletedAt *time.Time `sql:"index" json:"deleted_at"`
}

You would then populate this field using a method called before creation of any record, like so:

func (base *Base) BeforeCreate(scope *gorm.Scope) error {
 uuid, err := uuid.NewV4()
 if err != nil {
  return err
 }
 return scope.SetColumn("ID", uuid.String())
}

Therefore, for your particular case, you would have:

type User struct {
    Base
    FirstName string `form:"first_name" json:"first_name,omitempty"`
    LastName  string `form:"last_name" json:"last_name,omitempty"`
    Password  string `form:"password" json:"password" bindind:"required"`
    Email     string `gorm:"type:varchar(110);unique_index" form:"email" json:"email,omitempty" binding:"required"`
    Location  string `form:"location" json:"location,omitempty"`
    Avatar    string `form:"avatar" json:"avatar,omitempty"`
    BgImg     string `form:"bg_img" json:"bg_img,omitempty"`
}

More details on this can be found here