Evaluating the following integral should be non-zero, and mathematica correctly gives a non-zero result
Integrate[ Cos[ (Pi * x)/2 ]^2 * Cos[ (3*Pi*x)/2 ]^2, {x,
If you just drop the whole FullSimplify
part, mathematica does the integration neatly for you.
Integrate[
Cos[(Pi x)/2]^2 Cos[((2 n + 1) Pi x)/2] Cos[((2 m + 1) Pi x)/
2], {x, -1, 1}]
To include the condition that m
and n
are integers, it's better to use the Assumptions
option in Integrate
.
Integrate[
Cos[(Pi x)/2]^2 Cos[((2 n + 1) Pi x)/2] Cos[((2 m + 1) Pi x)/
2], {x, -1, 1}, Assumptions -> Element[{m, n}, Integers]]