Inverted arguments in scanf()

Question

I was (quickly) writing some code and accidently inverted the arguments in scanf():

char i[] = \"ABC1\\t\";
scanf(i, \"%s\");

Comp

Answer 1

I suppose it shouldn't.

int scanf ( const char * format, ... );

i was normally converted to a const char*, all the rest parameters are just "ellipsis" and cannot be checked at compile time.