I would like to make an ImageView display an image on a website. So I create a new ImageView and execute imgView.setImageURI(uri);
When I launch the app the
If it's not a content URI, this link may help. It seems to indicate that imgView.setImageURI()
should not be used for regular URIs. Copying in the relevant bit:
Yes,
ImageView.setImageURI(ContentURI uri)
works, but it is for content URIs particular to the Android platform, not URIs specifying Internet resources. The convention is applied to binary objects (images, for example) which cannot be exposed directly through a ContentProvider's Cursor methods. Instead, a String reference is used to reference a distinct content URI, which can be resolved by a separate query against the content provider. The setImageURI method is simply a wrapper to perform those steps for you.I have tested this usage of
setImageView
, and it does work as expected. For your usage, though, I'd look atBitmapFactory.decodeStream()
andURL.openStream()
.
Also to make this answer self-contained, the sample code from another post at that link, showing how to do it:
private Bitmap getImageBitmap(String url) {
Bitmap bm = null;
try {
URL aURL = new URL(url);
URLConnection conn = aURL.openConnection();
conn.connect();
InputStream is = conn.getInputStream();
BufferedInputStream bis = new BufferedInputStream(is);
bm = BitmapFactory.decodeStream(bis);
bis.close();
is.close();
} catch (IOException e) {
Log.e(TAG, "Error getting bitmap", e);
}
return bm;
}
I haven't tested this code, I'm just paranoid and like to ensure SO answers are useful even if every other site on the net disappears :-)