I\'m trying to search through a specific directory full of header files, and look through each header file, and if any file has a string \"struct\" in it, I just want the progra
It seems you are interested in the file name, not the line, so we can speed thing up by reading the whole file and search:
...
for file in glob.glob('*.h'):
with open(file) as f:
contents = f.read()
if 'struct' in contents:
print file
Using the with
construct ensures the file to be closed properly. The f.read() function reads the whole file.
Since the original poster stated that his code was not printing, I suggest to insert a debugging line:
...
for file in glob.glob('*.h'):
print 'DEBUG: file=>{0}<'.format(file)
with open(file) as f:
contents = f.read()
if 'struct' in contents:
print file
If you don't see any line that starts with 'DEBUG:', then your glob() returned an empty list. That means you landed in a wrong directory. Check the spelling for your directory, along with the directory's contents.
If you see the 'DEBUG:' lines, but don't see the intended output, your files might not have any 'struct' in in. Check for that case by first cd to the directory, and issue the following DOS command:
find "struct" *.h