Recursively replace characters in a dictionary

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难免孤独
难免孤独 2021-02-19 11:19

How do I change all dots . to underscores (in the dict\'s keys), given an arbitrarily nested dictionary?

What I tried is write two loops, b

2条回答
  •  遥遥无期
    2021-02-19 11:35

    Assuming . is only present in keys and all the dictionary's contents are primitive literals, the really cheap way would be to use str() or repr(), do the replacement, then ast.literal_eval() to get it back:

    d ={
        "brown.muffins": 5,
        "green.pear": 4,
        "delicious_apples": {
            "green.apples": 2
        } # correct brace
    }
    

    Result:

    >>> import ast
    >>> ast.literal_eval(repr(d).replace('.','_'))
    {'delicious_apples': {'green_apples': 2}, 'green_pear': 4, 'brown_muffins': 5}
    

    If the dictionary has . outside of keys, we can replace more carefully by using a regular expression to look for strings like 'ke.y': and replace only those bits:

    >>> import re
    >>> ast.literal_eval(re.sub(r"'(.*?)':", lambda x: x.group(0).replace('.','_'), repr(d)))
    {'delicious_apples': {'green_apples': 2}, 'green_pear': 4, 'brown_muffins': 5}
    

    If your dictionary is very complex, with '.' in values and dictionary-like strings and so on, use a real recursive approach. Like I said at the start, though, this is the cheap way.

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