Exception propagation and std::future

Question

My understanding is that when an asynchronous operation throws an exception, it will be propagated back to a thread that calls std::future::get(). However, when su

Answer 1

It is ignored and discarded, just like if you wait() for a value but never get() it.

wait() simply says "block until the future is ready", be that ready with a value or exception. It's up to the caller to actually get() the value (or exception). Usually you'll just use get(), which waits anyway.