How to wrap sublist with jaxb

Question

When trying to map a customer-> order 1:n relationship with jaxb 2.2.6 I\'d like to get the list of orders wrapped in a separate node \"orders\".

currently the result is

Answer 1

This seems to do the trick:

  @XmlElementWrapper(name="orders")
  @XmlElement(name="order", type=OrderJaxbDao.class)
  public List getOrders() { return orders; };

improved CustomerJaxbDao

/**
 * Copyright (C) 2011-2012 BITPlan GmbH
 * 
 * http://www.bitplan.com
 * 
 * generated: 2012-10-16 12:20 with smartGENERATOR
 */
package com.bitplan.testentity.jaxb;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlElement;
import com.bitplan.testentity.Customer;

import java.util.List;
import com.bitplan.testentity.Order;
import javax.xml.bind.annotation.XmlElementWrapper;
import java.util.ArrayList;

/**
 * JaxB Data access object for Customer
 * Entity: Customer for container testentity
 * Table: Customer
 */
@XmlRootElement(name="Customer")
public class CustomerJaxbDao implements Customer {
  /**
   * name
   */
  private String name;

  /**
   * id
   */
  private long id;

  /**
   * orders
   */
  private List orders=new ArrayList();

  /**
   * getter for name
   * @return name
   */
  @XmlElement(name="name")  
  public String getName() { return name; };

  /**
   * setter for name
   * @param pname - new value for name
   */
  public void setName(String pname) { name=pname; };

  /**
   * getter for id
   * @return id
   */
  @XmlElement(name="id")  
  public long getId() { return id; };

  /**
   * setter for id
   * @param pid - new value for id
   */
  public void setId(long pid) { id=pid; };

  /**
   * getter for orders
   * @return orders
   */
  @XmlElementWrapper(name="orders")
  @XmlElement(name="order", type=OrderJaxbDao.class)
  public List getOrders() { return orders; };

  /**
   * setter for orders
   * @param porders - new value for orders
   */
  public void setOrders(List porders) { orders=porders; };


} // CustomerJaxbDao