subscript operator on pointers

Question

If I have a pointer to an object that has an overloaded subscript operator ([]) why can\'t I do this:

 MyClass *a = new MyClass();
 a[1];
         


        

Answer 1

Good news. You can also do...

a->operator[](1);

To add on to the preferred answer, think of operator overloading as overloading functions.

When overloading member function of a class, you remember that the pointer is not of that class type.