Inefficient SQL Query

Question

I\'m building a simple web app at the moment that I\'ll one day open source. As it stands at the moment, the nav is generated on every page load (which will change to be cached

Answer 1

It should print completely the same code as your example

$navQuery = $mysqli->query("SELECT t1.id AS cat_id,t1.slug,t1.name AS cat_name,t2.id,t2.name
    FROM categories AS t1
    LEFT JOIN snippets AS t2 ON t1.id = t2.category
    WHERE t1.live=1
    ORDER BY t1.name ASC, t2.name ASC") or die(mysqli_error($mysqli));

$current = false;

while($nav = $navQuery->fetch_object()) {
    if ($current != $nav->cat_id) {
        if ($current) echo '