Python closure function losing outer variable access

Question

I just learned python @ decorator, it\'s cool, but soon I found my modified code coming out weird problems.

def with_wrapper(param1):
    def dummy_wrapper(fn):
         


        

Answer 1

Handy for temporary situations or exploratory code (but otherwise not good practice):

If you're wanting to capture a variable from the outer scope in Python 2.x then using global is also an option (with the usual provisos).

While the following will throw (assignment of outer1 within inner makes it local and hence unbounded in the if condition):

def outer():
    outer1 = 1
    def inner():
        if outer1 == 1:
            outer1 = 2
            print('attempted to accessed outer %d' % outer1)

This will not:

def outer():
    global outer1
    outer1 = 1
    def inner():
        global outer1
        if outer1 == 1:
            outer1 = 2
            print('accessed outer %d' % outer1)