Java logical operator (&&, ||) short-circuit mechanism

Question

As I was reading a colleague\'s Java code, I stumbled upon an army of if/else statements. In these statements, several && and || operators wer

Answer 1

Because of the precedence of && on ||, (true || true && false) this will be evaluated as (true || (true && false)) -> (true || (false)) -> true

See the precedences rules: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/operators.html