Java logical operator (&&, ||) short-circuit mechanism

Question

As I was reading a colleague\'s Java code, I stumbled upon an army of if/else statements. In these statements, several && and || operators wer

Answer 1

According to Java tutorials && has higher precedence over ||

So your true || true && false would be evaluated as true || (true && false)

And your false && true || true would be evaluated as (false && true) || true

Resulting in an output of true in both case.