Select record between two IP ranges

Question

I have a table which stores a ID, Name, Code, IPLow, IPHigh such as:

1, Lucas, 804645, 192.130.1         


        

Answer 1

Use below to fetch the ipLow / IPHigh in 4 columns. You can use those columns to compare Ips.

DECLARE@ip VARCHAR(50)='192.168.0.81' 
SELECT (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip))))

,
substring((REPLACE(@ip, (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip)) + 1)),
'')),
0,
patindex('%.%',
((REPLACE(@ip, (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip)) + 1)),
''))))),
SUBSTRING((SUBSTRING(@ip, LEN((SUBSTRING((@ip), 0,
patindex('%.%',
(@ip))))) + 2 + LEN(substring((REPLACE(@ip, (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip)) + 1)),
'')),
0,
patindex('%.%',
((REPLACE(@ip, (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip)) + 1)),
'')))))) + 1,
LEN(@IP) - 1 - LEN(reverse(SUBSTRING(reverse(@ip), 0,
patindex('%.%',
reverse(@ip))))))), 0,
PATINDEX('%.%',
(SUBSTRING(@ip, LEN((SUBSTRING((@ip), 0,
patindex('%.%',
(@ip))))) + 2 + LEN(substring((REPLACE(@ip, (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip)) + 1)),
'')),
0,
patindex('%.%',
((REPLACE(@ip, (SUBSTRING((@ip), 0,
patindex('%.%',
(@ip)) + 1)),
'')))))) + 1,
LEN(@IP) - 1 - LEN(reverse(SUBSTRING(reverse(@ip), 0,
patindex('%.%',
reverse(@ip))))))

))),
reverse(SUBSTRING(reverse(@ip), 0,
patindex('%.%',
reverse(@ip))))