Select record between two IP ranges

Question

I have a table which stores a ID, Name, Code, IPLow, IPHigh such as:

1, Lucas, 804645, 192.130.1         


        

Answer 1

With this function you can transform any IP address to a form where each part has 3 digits. With this you could do a normal alphanumeric compare. if you want you could return BIGINT too...

CREATE FUNCTION dbo.IPWidth3(@IP VARCHAR(100))
RETURNS VARCHAR(15)
BEGIN
DECLARE @RetVal VARCHAR(15);
WITH Splitted AS
(
    SELECT CAST('' + REPLACE(@IP,'.','') + '' AS XML) AS IPSplitted 
)
SELECT @RetVal = STUFF(
        (
        SELECT '.' + REPLACE(STR(Part.value('.','int'),3),' ','0')
        FROM Splitted.IPSplitted.nodes('/x') AS One(Part)
        FOR XML PATH('')
        ),1,1,'') 
FROM Splitted;

RETURN @RetVal;
END
GO

DECLARE @IP VARCHAR(100)='192.43.2.50';
SELECT dbo.IPWidth3(@IP);

The result

192.043.002.050

To reflect Ed Harper's comment here the same function returning a DECIMAL(12,0):

CREATE FUNCTION dbo.IP_as_Number(@IP VARCHAR(100))
RETURNS DECIMAL(12,0)
BEGIN
DECLARE @RetVal DECIMAL(12,0);
WITH Splitted AS
(
    SELECT CAST('' + REPLACE(@IP,'.','') + '' AS XML) AS IPSplitted 
)
SELECT @RetVal = 
        CAST((
        SELECT REPLACE(STR(Part.value('.','int'),3),' ','0')
        FROM Splitted.IPSplitted.nodes('/x') AS One(Part)
        FOR XML PATH('')
        ) AS DECIMAL(12,0))
FROM Splitted;

RETURN @RetVal;
END
GO

DECLARE @IP VARCHAR(100)='192.43.2.50';
SELECT dbo.IP_as_Number(@IP);