Raise two errors at the same time

Question

Is there any way to raise two errors at the same time by using try and except? For example, ValueError and KeyError.

How do I do that?

Answer 1

The solution from @shrewmouse still requires to choose an exception class to wrap the caught exceptions.

• Following solution uses Exception Chaining via finally to execute code after one exception occurs
• We don't need to know beforehand, what exceptions occur
• Note that only the first exception that occurs can be detected from the caller via except
  • if this is a problem, use @Collin's solution above to inherit from all collected exceptions
• You'll see the exceptions separated by:
  "During handling of the above exception, another exception occurred:"

def raise_multiple(errors):
    if not errors:  # list emptied, recursion ends
        return
    try:
        raise errors.pop()  # pop removes list entries
    finally:
        raise_multiple(errors)  # recursion

---

If you have a task that needs to be done for each element of a list, you don't need to collect the Exceptions beforehand. Here's an example for multiple file deletion with multiple error reporting:

def delete_multiple(files):
    if not files:
        return
    try:
        os.remove(files.pop())
    finally:
        delete_multiple(files)

---

PS:
Tested with Python 3.8.5
To print full traceback per exception have a look at traceback.print_exc
The original question is answered since years. But as this page is the top search result for "python raise multiple" I share my approach to fill an (IMHO relevant) gap in the solution spectrum.