PHP - If number is divisible by 3 and 5 then echo

Question

I\'m new to PHP and trying to create the following whilst minimizing the amount of code needed. PHP should show a list of 100 then display if the number is / by 3, 5 or 3 and 5.

Answer 1

This is neater and completed to be run:

";
                }
                elseif ($i%3==0)
                {
                    echo"Divisible by 3
";
                }
                elseif ($i%5==0)
                {
                    echo"Divisible by 5
";
                }
                else
                {
                    echo $i,"
";
                }

}
?>