PHP - If number is divisible by 3 and 5 then echo

Question

I\'m new to PHP and trying to create the following whilst minimizing the amount of code needed. PHP should show a list of 100 then display if the number is / by 3, 5 or 3 and 5.

Answer 1

No need to do three if statements:

echo "";

for ($i = 1; $i <= 100; $i++) {

    echo "\n";
}
echo "
{$i}
";

    if ($i % 3 == 0) echo "BY3 ";
    if ($i % 5 == 0) echo "BY5";

    echo "
";