PHP - If number is divisible by 3 and 5 then echo

Question

I\'m new to PHP and trying to create the following whilst minimizing the amount of code needed. PHP should show a list of 100 then display if the number is / by 3, 5 or 3 and 5.

Answer 1

$num_count = 100;
    $div_3 = "Divisible by 3";
    $div_5 = "Divisible by 5";
    $div_both = "Divisible by 3 and 5";
    $not_div = "Not Divisible by 3 or 5";

    for($i=0;$i<=$num_count;$i++)
    {
        switch($i)
        {
            case ($i%15==0):
            echo $i." (".$div_both.")
";
            break;
            case ($i%3==0):
            echo $i." (".$div_3.")
";
            break;
            case ($i%5==0):
            echo $i." (".$div_5.")
";
            break;
            default:
            echo $i."
";
            break;
        }
    }