PHP - If number is divisible by 3 and 5 then echo

Question

I\'m new to PHP and trying to create the following whilst minimizing the amount of code needed. PHP should show a list of 100 then display if the number is / by 3, 5 or 3 and 5.

Answer 1

if I'm reading your question correct then you are looking for :

if ($number % 3 == 0 && $number %5 == 0) {
        echo "BY3 AND 5";
} elseif ($number % 3 == 0)  {
    echo "BY3";
} elseif ($number % 5 == 0) {
    echo "BY5";
}

Alternative version :

echo ($number % 3 ? ($number % 5 ? "BY3 and 5" : "BY 3") : ($number % 5 ? "BY 5" : ""));