Removing whitespaces in a CSV file

Question

I have a string with extra whitespace:

First,Last,Email  ,Mobile Phone ,Company,Title  ,Street,City,State,Zip,Country, Birthday,Gender ,Contact Type

Answer 1

CSV supports "converters" for the headers and fields, which let you get inside the data before it's passed to your each loop.

Writing a sample CSV file:

csv = "First,Last,Email  ,Mobile Phone ,Company,Title  ,Street,City,State,Zip,Country, Birthday,Gender ,Contact Type
first,last,email  ,mobile phone ,company,title  ,street,city,state,zip,country, birthday,gender ,contact type
"
File.write('file_upload_example.csv', csv)

Here's how I'd do it:

require 'csv'
csv = CSV.open('file_upload_example.csv', :headers => true)
[:convert, :header_convert].each { |c| csv.send(c) { |f| f.strip } }

csv.each do |row|
  puts "First Name: #{row['First']} \nLast Name: #{row['Last']} \nEmail: #{row['Email']}"
end

Which outputs:

First Name: 'first'
Last Name: 'last'
Email: 'email'

The converters simply strip leading and trailing whitespace from each header and each field as they're read from the file.

Also, as a programming design choice, don't read your file into memory using:

csv_text = File.read('file_upload_example.csv')

Then parse it:

csv = CSV.parse(csv_text, :headers => true)

Then loop over it:

csv.each do |row|

Ruby's IO system supports "enumerating" over a file, line by line. Once my code does CSV.open the file is readable and the each reads each line. The entire file doesn't need to be in memory at once, which isn't scalable (though on new machines it's becoming a lot more reasonable), and, if you test, you'll find that reading a file using each is extremely fast, probably equally fast as reading it, parsing it then iterating over the parsed file.