Trim a trailing .0

Question

I have an Excel column containing part numbers. Here is a sample

As you can see, it can be many differ

Answer 1

def trim num
  i, f = num.to_i, num.to_f
  i == f ? i : f
end

trim(2.5) # => 2.5
trim(23) # => 23

or, from string:

def convert x
  Float(x)
  i, f = x.to_i, x.to_f
  i == f ? i : f
rescue ArgumentError
  x
end

convert("fjf") # => "fjf"
convert("2.5") # => 2.5
convert("23") # => 23
convert("2.0") # => 2
convert("1.00") # => 1
convert("1.10") # => 1.1