C++ char*[] to char** conversion

Question

I have this simple code that compiles without errors/warnings:

void f(int&, char**&){}

int main(int argc, char* argv[])
{
    f(argc, argv);
    return          


        

Answer 1

The type of temp in

char* temp[] = { "", "", nullptr };

is not char*[], it's

char*[3]

The latter can't be implicitly converted to `char**'.

In main, the type of argv is an unbound char* array which is equivalent to char**

I admit, it's confusing :)