Is it possible to assign two variables in Perl foreach loop?

Question

Is it possible to assign two variables the same data from an array in a Perl foreach loop?

I am using Perl 5, I think I came across something in Perl 6.

Somethi

Answer 1

The easiest way to use this is with a while loop that calls splice on the first two elements of the array each time,

while (my($var1, $var2) = splice(@array, 0, 2)) {
    ...
}

However, unlike foreach, this continually does a double-shift on the original array, so when you’re done, the array is empty. Also, the variables assigned are copies, not aliases as with foreach.

If you don’t like that, you can use a C-style for loop:

for (my $i = 0; $i < @array; $i += 2) {
     my($var1, $var2) = @array[$i, $i+1];
     ...
}

That leaves the array in place but does not allow you to update it the way foreach does. To do that, you need to address the array directly.

my @pairlist = (
    fee => 1,
    fie => 2,
    foe => 3,
    fum => 4,
);

for (my $i = 0; $i < @pairlist; $i += 2) {
    $pairlist[ $i + 0 ] x= 2;
    $pairlist[ $i + 1 ] *= 2;
}

print "Array is @pairlist\n";

That prints out:

Array is feefee 2 fiefie 4 foefoe 6 fumfum 8

You can get those into aliased variables if you try hard enough, but it’s probably not worth it:

my @kvlist = ( 
    fee => 1,
    fie => 2,
    foe => 3,
    fum => 4,
);

for (my $i = 0; $i < @kvlist; $i += 2) { 
    our  ($key, $value);
    local(*key, $value) = \@kvlist[ $i, $i + 1 ];
    $key   x= 2;
    $value *= 2;
}

print "Array is @kvlist\n";

Which prints out the expected changed array:

Array is feefee 2 fiefie 4 foefoe 6 fumfum 8

Note that the pairs offered by the List::Pairwise module, which were but very recently added to the core List::Util module (and so you probably cannot use it), are still not giving you aliases:

use List::Util 1.29 qw(pairs);

my @pairlist = (
    fee => 1,
    fie => 2,
    foe => 3,
    fum => 4,
);

for my $pref (pairs(@pairlist)) {
    $pref->[0] x= 2;
    $pref->[1] *= 2;
}

print "Array is @pairlist\n";

That prints out only:

Array is fee 1 fie 2 foe 3 fum 4

So it didn’t change the array at all. Oops. :(

Of course, if this were a real hash, you could double the values trivially:

for my $value (values %hash) { $value *= 2 }

The reasons that works is because those are aliases into the actual hash values.

You cannot change the keys, since they’re immutable. However, you can make a new hash that’s an updated copy of the old one easily enough:

my %old_hash = (
    fee => 1,
    fie => 2,
    foe => 3,
    fum => 4,
);

my %new_hash;    
@new_hash{ map { $_ x 2 } keys   %old_hash } = 
           map { $_ * 2 } values %old_hash;

print "Old hash is: ", join(" " => %old_hash), "\n";
print "New hash is: ", join(" " => %new_hash), "\n";

That outputs

Old hash is: foe 3 fee 1 fum 4 fie 2
New hash is: foefoe 6 fiefie 4 fumfum 8 feefee 2