How do I find full path to an application in a batch script

Question

How do I in a batch script find the full path to application XYZ if it is installed

Clarifications:

1. The application is not in the PATH
2. All I h

Answer 1

Based on the really helpful answers here I hacked up these two batches which I thought I share here (I know this thread is now 3 years old, but its found as 1st match when googling ...):

1) which.bat:

@echo off
REM emulate the Linux which command
if "%1" == "" (
  echo Usage: %~nx0 ^
  exit /b
)
setlocal
for %%P in (%PATHEXT%) do (
  for %%I in (%1 %1%%P) do (
    if exist "%%~$PATH:I" (
      echo %%~$PATH:I
      exit /b
    )
  )
)

not perfect because there are allways two tests, but its fast enough so I didnt further bother about; sure its possible to 1st do a separate test with %1 only ...

2) findfile.bat:

@echo off
REM emulate the Linux find command
if "%1" == "" (
  echo Usage: %~nx0 ^ ^
  exit /b
)
setlocal
for /f "delims=" %%A in ('dir /b /s %1\%2') do set F=%%A
if exist "%F%" echo %F%