Ordering in an initialization in C, C++

Question

Consider the following initializations:

/* C, C++ */
int a[] = { f(), g() };
struct { int x, y } foo = { f(), g() };

/* C++ */
struct goo { goo(int x, int y);           


        

Answer 1

In all these two cases

goo b = { f(), g() };
goo c { f(), g() };    /* C++11 */

the order of evaluation is determined from left to right and all side effects shall be applied before the next initializer.

From the C++ STandard

4 Within the initializer-list of a braced-init-list, the initializer-clauses, including any that result from pack expansions (14.5.3), are evaluated in the order in which they appear. That is, every value computation and side effect associated with a given initializer-clause is sequenced before every value computation and side effect associated with any initializer-clause that follows it in the comma-separated list of the initializer-list.

However in C there is other rule

The evaluations of the initialization list expressions are indeterminately sequenced with respect to one another and thus the order in which any side effects occur is unspecified.