I\'m currently working on a pygame game and I need to place objects randomly on the screen, except they cannot be within a designated rectangle. Is there an easy way to do this
I've already posted a different answer that I still like, as it is simple and clear, and not necessarily slow... at any rate it's not exactly what the OP asked for.
I thought about it and I devised an algorithm for solving the OP's problem within their constraints:
divmod
determine the column and the row (dx, dy) in the tileTo implement the ideas above, in which there is an initialization phase in which we compute static data and a phase in which we repeatedly use those data, the natural data structure is a class, and here it is my implementation
from random import randrange
class make_a_hole_in_the_screen():
def __init__(self, screen, hole_orig, hole_sizes):
xs, ys = screen
x, y = hole_orig
wx, wy = hole_sizes
tiles = [(_y,_x*_y) for _x in [x,wx,xs-x-wx] for _y in [y,wy,ys-y-wy]]
self.tiles = tiles[:4] + tiles[5:]
self.pixels = [tile[1] for tile in self.tiles]
self.total = sum(self.pixels)
self.boundaries = [sum(self.pixels[:i+1]) for i in range(8)]
self.x = [0, 0, 0,
x, x,
x+wx, x+wx, x+wx]
self.y = [0, y, y+wy,
0, y+wy,
0, y, y+wy]
def choose(self):
n = randrange(self.total)
for i, tile in enumerate(self.tiles):
if n < self.boundaries[i]: break
n1 = n - ([0]+self.boundaries)[i]
dx, dy = divmod(n1,self.tiles[i][0])
return self.x[i]+dx, self.y[i]+dy
To test the correctness of the implementation, here it is a rough check that I
run on python 2.7
,
drilled_screen = make_a_hole_in_the_screen((200,100),(30,50),(20,30))
for i in range(1000000):
x, y = drilled_screen.choose()
if 30<=x<50 and 50<=y<80: print "***", x, y
if x<0 or x>=200 or y<0 or y>=100: print "+++", x, y
A possible optimization consists in using a bisection algorithm to find the relevant tile in place of the simpler linear search that I've implemented.